11/05/2020
Prove
Proof:
Take the three centers of the circles:
From the Law of Cosines:
From the Law of Sines:
Proof 2
11/06/2020
Solution:
Make equilateral triangle
11/07/2020
Solution:
Let
So
Therefore,
11/08/2020
Solution:
Solution:
11/09/2020
The distance from a point D inside equilateral triangle
Solution 1:
Rotate
Then
Then we know
Solution 2:
Rotate
Easy to find that
So
According to Heron’s formula :
And we know
So we have
11/10/2020
is equilateral. Point is outside and , . Prove
Make circumcircle of
-
Point
and cannot be on the same side of line , so and are on the same side of line . -
So is also equilateral.
From 1 and 2 we know
11/12/2020
A semicircle is constructed on line segment . Another semicircle is constructed on chord , intersecting at and . If , , and , then find the length .
Solution 1:
Solution 2:
11/13/2020
Point D is outside of circle O with diameter MN. From D make two lines DM and DB with points D, A and B on the circle O. Extend OD and NA to intersect at point C. Prove that
11/14/2020
Let be an acute triangle with circumcircle , and let be the intersection of the altitudes of . Suppose the tangent to the circumcircle of at intersects at points and with , , and . the area of can be written in the form , where and are positive integers, and is not divisible by the square of any prime. Find .
11/15/2020
Find all primes to make is a perfect square.
Solution:
If
11/16/2020
A scale model of a building is 8 inches wide and 27 inches tall. It is placed against a wall. What is the length of the shortest pole that will reach the wall above it from the level ground?
Solution 1:
Use trigonometry it is easier to get
Note: to avoid trigonometrical approach, it would be a hard work to solve this problem, seems.
Solution 2:
Get another solution based on another problem on 11/30/2020:
Suppose
11/17/2020
How many sequences of integers are there for which for every , and ?
11/18/2020
There are 12 students in a classroom: 6 of them are Democrats and 6 of them are Republicans. Every hour the students are randomly separated into four groups of three for political debates. If a group contains students from both parties, the minority in the group will change his/her political alignment to that of the majority at the end of the debate. What is the expected amount of time needed for all 12 students to have the same political alignment, in hours? (HMMT November 2017 Team Round Problem 7)
Solution:
11/22/2020
Point is the incenter of and point bisects side . Extend line IM and intersects circumcircle of at point . Point and bisects the arc and . Line intersects at point , Line intersects at point . Prove:
Proof:
Point
Point
11/23/2020
In a single-elimination tournament consisting of teams, there is a strict ordering on the skill levels of the teams, but Joy does not know that ordering. The teams are randomly put into a bracket and they play out the tournament, where the better team always beats the worse team. Joy is then given the results of all matches and must write a list of teams such that she can guarantee that the third-best team is on the list. What is the minimum possible length of Joy’s list (Shared by Brady from HMMT Guts Test November 2020)
Solution:
After understanding the model, easy to know that, checking the result of all
The second best team must be one of those teams who lost to the first team - because only the best team can win it. There are 9 teams in this set.
The third best team has two situations:
- It could be one of the teams who lost to the first team - it could be in the 9-team-set.
- Or, it could be one of the teams who lost to any team from the 9-team-set.
Check the teams in the 9-team-set:
- There is a team lost in the 1st round, and 0 team lost to it.
- There is a team lost in the 2nd round, and 1 team lost to it.
- There is a team lost in the 3rd round, and 2 teams lost to it.
- …
- There is a team lost in the 9th round, and 8 teams lost to it.
So totally there are
To include two situations for the third best team, we need the list length no shorter than
11/24/2020
Point bisects side in and , prove:
Proof:
Let point
and we already know
so
11/25/2020
and are angle bisectors of and . Prove
Proof 1:
Let
From Length of Angle Bisector:
Proof 2:
Draw
Draw
Proof 3:
Assume
Through point
The assumption of the inequality of
Therefore,
11/27/2020
A sphere is centered at a point with integer coordinates and passes through the three points , but not the origin . If is the smallest possible radius of the sphere, compute . (HMMT General, November 2020)
Solution:
Suppose the center of the sphere is
If
The closest odd integer to
but
The second closest odd integer to
and
So the solution is
11/30/2020
Solve over the integers:
Solution:
Easy to see
Suppose
So the answer is
11/30/2020
Solution:
So